1 SOLVE THE FOLLOWING A. A proton is released at x =2 m in a constant electric f
ID: 1771993 • Letter: 1
Question
1 SOLVE THE FOLLOWING
A. A proton is released at x =2 m in a constant electric field of strength 1000 N/C acting in the positive x direction. What is the change in the electric potential associated with the proton after it travels to x = 5 m?
B.A 250 N/C uniform electric field is created between two plates that are separated by 6 cm. Find the work done by the electric force on an electron that moves from the positive plate to the negative plate.
C.A 175 N/C uniform electric field is created between two plates that are separated by 4 cm. Find the work done by the electric force on an electron that moves from the positive plate to the negative plate.
Explanation / Answer
A)
Given E = 1000 N/c
the distance travelled by proton is d = 5-2 = 3 m
the electric potential is
V = E * d = 1000 * 3
V = 3000 V
B)
E = 250 N/C
d = 6 cm = 0.06 m
the potential difference v = 250 * 0.06
V = 15 V
the work done on an electron is
W = -e * V
W = - 1.6 * 10^-19 * 15
W = 2.4 * 10^-18 J
c)
E = 175 N/C
d = 4 cm = 0.04 m
the potential difference v = 175 * 0.04
V = 7 V
the work done on an electron is
W = -e * V
W = - 1.6 * 10^-19 * 7
W = 1.12 * 10^-18 J
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