please help! ! with details and answer second and revolutions per second? per 3)

Question

please help! ! with details and answer

second and revolutions per second? per 3) Projectile motion 10.0) (in meters). A heavy projectile is launched from O = (0,0,0) to hit a target at rT =(5, Make a drawing and the fixed target. g of the implied coordinate system, including the initial position of the projectile at should be the initial velocity vector for the projectile so that it both hits the target and its initial speed is as low as possible? . Wh ° The target changes the y component of the velocity of the projectile to vy- -0.1 meters/sec and releases it. How many seconds later does the projectile touch the ground again?

Explanation / Answer

Speed is lowest when target iis hit at its maximum. height.

10 = ( u sin theta)^2/2g

u sin theta = uy = sqrt(10*2*9.8) = 14 m/s

time taken = 14/9.8 = 1.429

horizontal speed Vx = 5/1.429 = 3.5 m/s

V = sqrt(14^2+3.5^2) = 14.43 m/s answer

-10 = -0.1t - 0.5*9.8 t^2

t = 1.418 s

total time from launching to hitting ground again = 1.429+1.418 = 2.827 s

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