oo T-Mobile @ 62%. 10:50 PM spock.physast.uga.edu An airplane of mass 14900 kg i

Question

oo T-Mobile @ 62%. 10:50 PM spock.physast.uga.edu An airplane of mass 14900 kg is flying in a straight line at a constant altitude and with a speed of 470.0 km/hr. The force that keeps the airplane in the air is provided entirely by the aerodynamic lift generated by the wings. The direction of this force is perpendicular to the wing surface. Calculate the magnitude of the lift generated by the wings of this airplane 2 206500N Submit Answer Incorrect. Tries 2/8 Previous Tries To change the direction of the plane, its wings are banked. If the wings of the plane are banked 45.0° to the horizontal, what is the radius of the circle in which the plane will be flying? Assume that the speed remains 470.0 km/hr during the turn and that the magnitude of the lift provided by the wings is unchanged. Submit Answer Tries o/8 What is the magnitude of the vertical acceleration that the airplane experiences as a result of the turn? Submit Answer Tries o/8 Post Discussion Send Feedback

Explanation / Answer

Here ,

let the lift force is F

as the plane is not accelerating in the vertical direction

net force in vertical direction must be zero

hence , F - m * g = 0

F = 14900 * 9.8

F = 146000 N

the lift force is 146000 N

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speed of plane = 470 km/hr = 130.6 m/s

Now, let the radius is r

for centripetal force

F * cos(45 degree) = m * v^2/r

146000 * cos(45 degree) = 14900 * 130.6^2/r

solving for r

r = 2460 m

the radius of the circle is 2460 m

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magnitude of vertical acceleration = (mg - mg * sin(45 degree))/m

magnitude of vertical acceleration = 9.8 * (1 - sin(45 dgeree))

magnitude of vertical acceleration = 2.87 m/s^2

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