Secure l https://session.masteringphysics.com/myct/itemView?assignmentProblem C

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Secure l https://session.masteringphysics.com/myct/itemView?assignmentProblem C Exercise 4.77 Part A Unless otherwise stated all objests are located near the Eaths suface, whereg-9.80m/s n loading a fish delivery truck, a person pushes a block of ice up a 18 d incline a constant speed The push is 180 N in magnitude and paralel to he incline. The block has a mass of 370kg s the incline frictionless? no Correct Part B tnot what is the forse of kinetic friction on the block of ice Express your answer using two significant fgures

Explanation / Answer

Weight of ice block = mg = (37)(9.80) = 362.6 N acting perpendicular to the ground
Force of weight that acts DOWN and parallel to the incline = 362.6sin18 = 112.05 N = W
As block moves UP at CONSTANT speed, NET FORCE parallel to incline = 0
Kinetic Friction Force (KEF) acts opposite to 180 N UP incline force
180 N (UP incline) = W (DOWN incline) + KEF (DOWN incline)
180 = 112.05 + KEF
KEF = 180 - 112.05 = 67.95 N .. or 68 N rounded off

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