Problem 5. - Projectile Motion. An airplane is moving at a velocity v 360 km/h w
ID: 1771171 • Letter: P
Question
Explanation / Answer
u = 360 km/hr = 100 m/s
angle = -20
sy = 600 m
ux = 100*cos(20)
uy = - 100*sin(20)
A)
sy = ut + 1/2at^2
-600 = - 100*sin(20)*t +(1/2)*(-9.8)*t^2
t = 8.113 sec
B)
sx = ux*t
sx = 100*cos(20)*8.113
sx = 762.37 sec
Please upvote if the answer is correct
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