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https://session.masteringphysics.com/myct/itemview?assignmentProblemID-83003076 HW13-Chot 33Exercise 33.17 Resources Exercise 33.17 Part A The critical angle for total internal reflection at a liquid-air interface is 44.5 If a ray of light traveling in the liquid has an angle of incidence at the interface of 30.5,what angle does the refracted ray in the air make with the normal? Submit My Answers Give Up Part B If a ray of light traveling in air has an angle of incidence at the interface of 30.5 what angle does the refracted ray in the liquid make with the normal? Submit

Explanation / Answer

a) 1 / mu = sin 44.5

mu = 1.427

From snell's law, sin theta2 / sin theta1 = n1 / n2

sin theta = sin 30.5 * 1.427

theta = 46.4 deg

b) sin theta2 / sin theta1 = n1 / n2

sin theta = sin 30.5 * [1 / 1.427]

theta = 20.8 deg

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