Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

iPad 8:21 PM flipitphysics.com * 48%- An green bono with mass-2.4 kg and radius

ID: 1770922 • Letter: I

Question



iPad 8:21 PM flipitphysics.com * 48%- An green bono with mass-2.4 kg and radius R Q.15 m hangs from a string that goes over a blue solld dhk puiley with mass my 1.8 kg and radius Rg-0.09 m.The other end of the string is attached to a massless avel through the cerner or anorange sphere on af at honaontal tace that rolls without sappng and has mass,4.2 kg and radus , O19 m. The syntem is relemed from rest. 1) What is magnitude of the linear acceleration of the hooph 1.85 Your submisson 1.85X Submitted: Tunday. November 28 at 8:20 PM Computed value: 1.85 Feedback 2) what is magnitude of the tinear acceleration of the sphere What is he magnibude of the angular acceleracion of the disk pulley What is the magnitude of the angular acceleration of the sphere 5) What is the tension in the string between the sphere and disk pulley? What is the tension in the string between the hoop and disk pulley 7) The preen hoop fails a distance d-1.85 m. After bring released from rest How much time does the hoop take to fall 5.65 m What is the magnitude of the velocity of the green hoop after it has dropped 1.5m ) What is the magnitude of the final angular speed of the orange sphene ater the green hoop has fallen the 1.65mp

Explanation / Answer

F net = m x g = 2.4 x 9.81 = 23.54 N

I = 7/5 x mR^2

M = 7/5 x m

a = F/m = 23.54/(2.4 + 1/2 x 1.8 + 7/5 x 4.2) = 2.56 m/s^2

1) linear acceleration of hoop = 2.56 m/s^2

2) linear acceleration of sphere = 2.56 m/s^2

3) angular acceleration disk pulley, w = a/R = 2.56/0.09 = 28.44 rad/s^2

4) angular acceleration sphere, w = a/R = 2.56/0.19= 13.47 rad/s^2

5) tension between pulley and sphere = M x a = (7/5) x 4.2 x 2.56 = 15.053 N

6) tension between hoop and pulley = m(hoop) (g - a) = 2.4(9.81 - 2.56) = 17.4 N

7) t = sqrt(2s/a) = sqrt(2 x 1.65/2.56) = 1.135 seconds

8) v = sqrt(2as) = sqrt(2 x 2.56 x 1.65) = 2.906 m/s

9) w = v/R = 2.906/0.19 = 15.30 rad/s

Please rate my answer...