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/TakeTut 9:00 PM (13%) Problem 7: Suppose a wire is 21 m long with a 0.125mm dua

ID: 1770636 • Letter: #

Question

/TakeTut 9:00 PM (13%) Problem 7: Suppose a wire is 21 m long with a 0.125mm duameter and has a resistance of 96 at 20 0°C. Randomized Variables L-21 m R-96 Silver Copper Gold 0.4 x 10* 0,000 x 10 0.002 x 10 3.4 x 10 -0.5 x 10 Iron 5.0 x 10 Ssliom70 10 Ctheexpertta.com ag 50% Part (a) What is the resistivity ofthe wire's material? = Deductions Potential 100% Attemapts remaining 13 Glb per attempt) 11213 Degrees Radians Hint Hints: per 50% Part (b) what s its resistance at l 50°C, in ohms, tf the temperature coefficient of resstnity is the same as that of gold?

Explanation / Answer

Here,

part a)

let the resistivity is p

as R = p * L/Area

96 = p * 21/(pi * (0.125 *10^-3/2)^2)

solving for p

p = 5.61 *10^-8 Ohm.m

the resistivity of the material is 5.61 *10^-8 Ohm.m

b)

for gold , temperature coefficient of resistance , a = 34 *10^-4 1/degree C

Let the final resistance is R

R =RO * (1 + a * delta T)

R = 96 * (1 + 3.4 *10^-3 * (150 - 20))

R = 138 Ohm

the resistance is 138 Ohm