i need help with questions (a) and (b) i cant figure them out My NotesAsk -12 po

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i need help with questions (a) and (b) i cant figure them out

My NotesAsk -12 points LarColAlg8 3.5.045 Use Hooke's Law for springs, which states that the distance a spring is stretch (or compressed) varies directly as the force on the spring. A force of 265 newtons stretches a spring 0.15 meter (see figure) Equilibrium0.15 meter 265 newtons (a) How far will a force of 120 newtons stretch the spring? (Round your answer to two decimal places.) 007x Your answer cannot be understood or graded. More Informa (b) What force is required to stretch the spring 0.5 meter? (Round your answer to two decimal places.) 83.33x Your answer cannot be understood or graded. More Informa

Explanation / Answer

a] here spring constant k = F/x = 265/0.15 N/m

now the expansion x2 = F2/k = 120*0.15/265 = 0.068 m in two significant figure

= 0.07 m in two decimal places

b] F = kx = 265/0.15 *0.5 = 883.33 N in two decimal places.

F = 8.8*10^2 N in two significant figure

Note: Try entering answer in two significant figure.

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