two parallel plates are separated by a distance of 12.3 mm are connected to a 9
ID: 1769899 • Letter: T
Question
two parallel plates are separated by a distance of 12.3 mm are connected to a 9 volt battery. a proton is emitted from positive plate with an initial speed of 1.62x104 m/ At least one of the answers above is NOT correct. (5 points) Two parailel plates are separated by a distance of 12.3 mm are connected to a 9 volt atery A proton is emited trom posltive plate with an initial speed of 1.62 × 104 ms A) What is the speed of the proton when it is at a potential of 1.59 volts? what distance trom the negative plate is the proton when it is at a potential of 1.59 volts? (C) What is the magitude of the electric field between the plates? (D) What is the electric potential of the proton when it is 3.83 mm from the negative plate? (E) How fast is the proton moving when it is 3.83 mm from the negative plate? Your score was recorded You have attempted this problem 5 times You received a score of 0% for this atte Your overall recorded score is 0%Explanation / Answer
A] by energy conservation: 0.5 mv1^2 + qV1 = 0.5 mv2^2 + qV2
0.5*1.673e-27*1.62e4^2 + 1.6e-19*9 = 0.5*1.673e-27*v^2 + 1.6e-19*1.59
v = sqrt((0.5*1.673e-27*1.62e4^2 + 1.6e-19*9-1.6e-19*1.59)/(0.5*1.673e-27))
= 40985 m/s
B] x = d*1.59/9 = 12.3*1.59/9 = 2.173 mm
C] E = V/d = 9/0.0123 = 731.7 V/m
d] V = 9*3.83/12.3 = 2.802V
E) again using energy conservation,
0.5*1.673e-27*1.62e4^2 + 1.6e-19*9 = 0.5*1.673e-27*v^2 + 1.6e-19*2.802
v = sqrt((0.5*1.673e-27*1.62e4^2 + 1.6e-19*9-1.6e-19*2.802)/(0.5*1.673e-27))
= 38052 m/s
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