(1) Measure and record (at the summary page) the current flow through the circui
ID: 1769696 • Letter: #
Question
(1) Measure and record (at the summary page) the current flow through the circuit at various places, such between the battery and RA, between Ra and Rs. between Rs and battery. To measure the current, put the multimeter in current mode, break the circuit at the point you want to measure, and wire your circuit again to insert the multimeter at that point. Is the current "used up" as it goes around the circuit? what conservation principle would you use to explain Are the current the same? this? Verify Ohm's Law: Remove the multimeter from the circuit. Use the multimeter to measure potential difference across each capacitor. From your measured resistance value, predict the current flowing through each resistor and compared the (average) measured current. Fill out your answer in the summary page. PartIl, Potential changes around the cireuit Use the same circuit as part . Put the multimeter in voltmeter mode. Connect the black lead to the negative of the battery andtouch the red lead at various places as you go around the circuit to measure the potential (start with the + side of the battery.) Go to the summary page and make graph of potential and indicate various components and action as you go around the loop (as in your textbook.) What is V as you make a complete loop around the circuit?Explanation / Answer
Since in the above circuit everything is in series, the current will remain same at every point. The current is not used up as it goes around the circuit. The main principle behind this is the conservation of electic charge. As per the kirchoff's law of current whatever current is going out from the + terminal should come back to the - terminal.
According to ohm's law V=IR , you can find R by finding V and I as mentioned in the experiment. Since the value of R is already known, it can be easily verified.
As we measure the voltages drop across resistors using voltmeter, you will find that the total drop in the loop will be equal to the Voltage of the battery connected. Since V = I ( R1+ R2) in your case.
I have assumed the circuit mentioned in your image is closed. In open circuit no current will flow.
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