A double - changed helium atom is accelerated by the volatge v in the right boun

Question

A double - changed helium atom is accelerated by the volatge v in the right bound direction and then it enters the religion with the electric field E =200 V/ cm directed to the left. The ion penetrates into the region of the field by the distance l=10cm. What is the volatge V? A double - changed helium atom is accelerated by the volatge v in the right bound direction and then it enters the religion with the electric field E =200 V/ cm directed to the left. The ion penetrates into the region of the field by the distance l=10cm. What is the volatge V?

Explanation / Answer

If q is the charge on the Helium atom,
Kinetic energy after accelerated by the voltage V in the right-bound direction = qV
So, its velocity is towards right.
Now the electric field E = 200 V/cm is directed to the left and it will slow down the charge.
Force felt by the charge = qE
Workdone by E on the charge must cancel all the energy it had.

So, workdone by E = KE of the charge
=> qE x d = qV
=> V = Ed = 200 V/cm x 10cm = 2000V

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