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A 8.26-kg rocket with a charge of 7.30 mC rests on a horizontal plate. Another h

ID: 1769207 • Letter: A

Question

A 8.26-kg rocket with a charge of 7.30 mC rests on a horizontal plate. Another horizontal plate above the first has a hole directly above the rocket. A potential difference of 10.0 kV is established between the two plates, causing the rocket to rise into the air. What is the maximum height that the rocket rises before it comes crashing back to earth?

A 8.26-kg rocket with a charge of 7.30 mC rests on a horizontal plate. Another horizontal plate above the first has a hole directly above the rocket. A potential difference of 10.0 kV is established between the two plates, causing the rocket to rise into the air. What is the maximum height that the rocket rises before it comes crashing back to earth?

Explanation / Answer

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. Ifthis helps then kindly rate 5-stars.

A 8.80-kg rocket with a charge of 7.60 mC rests on a horizontal plate. Another horizontal plate above the first has a hole directly above the rocket. A potential difference of 10.0 kV is established between the two plates, causing the rocket to rise into the air. What is the maximum height that the rocket rises before it comes crashing back to earth?

answer

by applying conservation of energy
we have
electric pot energy lost=gravitational pot energy gained
hence
7.6*10=8.8*9.8*h
h=0.88 metres   

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