oooo TFW F 3:45 PM webassign.net In the following figure ca as ca 2.10 and ca-sa
ID: 1769030 • Letter: O
Question
oooo TFW F 3:45 PM webassign.net In the following figure ca as ca 2.10 and ca-sao The capacitor network is connected to an applied potential V After the charges on the capacitors have reached their final values, the charge on C2 is 60.0HC. (a) What are the charges on capacitors C1 and C3? c (b) What is the applied voltage Vab? The following figure shows a system of four capacitors, where the potential difference across ab is 50.0 V. (Let C1 13.0 HF, C2 4.0 F, C3 8.5 HF, and C 7.0 HF.) (a) Find the equivalent capacitance of this system between a and b. HF (b) How much charge is stored by this combination of capacitors? HC (c) How much charge is stored in each of C1 and C2? A parallel-plate air capacitor has a capacitance of 790 pF. The charge on each plate is 2.75 HC.Explanation / Answer
1.
a)
Charge on C2 is
Q2=Q*(C2/C1+C2)
60 =Q*(2.1/2.1+7.05)
Q=261.4 uC
Charge on C1 is
Q1=Q-Q2=261.4-60
Q1=201.4uC
Charge on C3 is
Q3=Q=261.4 uC
b)
equivalent capacitance
1/Ceq =1/(C1+C2) +1/C3=1/(2.1+7.05) +1/5.5
Ceq=3.44 uF
Applied voltage is
Vab=Q/Ceq=261.4/3.26
Vab=76.1 Volts
2.
equivalent capacitance
1/Ceq =1/C1 +1/(C2+C3)+1/C4 =1/13 +1/(4+8.5) +1/7
Ceq=3.34 uF
b)
Total Charge
Q=CeqV=3.34*50
Q=166.8 uC
c)
Charge on C1 is
Q1=Q=166.8 uC
Charge on C2 is
Q2=Q*(C2/C2+C3) =166.8*(4/4+8.5)
Q2=53.4 uC
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