Problem (1) For the circuit shown in Figure 1, The current in the 4.5 mH inducto

Question

Problem (1)

For the circuit shown in Figure 1, The current in the 4.5 mH inductor is known to be 1A for t < 0. The inductor voltage for t ? 0 is given by the expression:

vL (t) = 10e^(-5t)mV, 0^+ <= t <= 2 s

vL (t) = -10e^-5(t-3)mV, 2 <= t <= + infinity

1- Express the current across the terminals of the 4.5 mH inductor as a function of time

2- Sketch for ?vL (t) ?for 0 <= t <= + infinity

3- Sketch for ?IL (t) ?for?0 <= t <= + infinity

4- At what instant of time is the current maximum?

5- At what instant of time does the voltage change polarity?

Explanation / Answer

sorry you are not posting circuit figure... please repost the question totally.. after then i may give an answer..

thank you...

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