(1) Multiple choice and fill in blank questions (60 points, 4 points each) The m
ID: 1766484 • Letter: #
Question
(1) Multiple choice and fill in blank questions (60 points, 4 points each) The machining order (alpha beltaly) is shown in the part drawing. The part's origin is located at Point b. If the part is programmed in absolute mode and the process sequence is a >b>c>d >e>f>g, the coordinate of point g is 1. A. B. C. D. E. x=0.000, y = 1.50 x=4.000, y = 1.50 x=-1.75, y = 6.75 x-2.875, y = 1.50 None of the above Latch lock (0.25 thick MS) 4.000 Formed radius 2.875 1.750 60° 60° 2.51 1.50 -1 1.50 01 02 c 1.12 0 0.375 0.85 1.00 -2.00- 2. In above question, if the part is programmed in incremental mode, the coordinate of point is: A. B. C. D. E. x =-2.75, y = 1.50 x = 1.125, y=-085 x=-1.125, y=0.65 x =-1.125, y=-0.65 None of aboveExplanation / Answer
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In absolute mode, the positioning is done with respect to origin while in incremental mode positioning is achieved by considering the previous position oonly.
Therefore, in absolute mode the coordinate of point g is x=-4 , y=1,5 as point b is the origin. Hence for first question option B is correct.
For second question, we have to use incremental mode. Therefore, seeing the operation sequence we can define positionof each point as shown below
Hence option C is correct.
in case of any doubt, do comment below
point coordinate(x,y) a 0.0 b 4,0 c 4,1.85 d -1.125, 0.64Related Questions
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