A man with dwarfism marries a dwarf and they have children. What proportion of t

Question

A man with dwarfism marries a dwarf and they have children. What proportion of the surviving progeny will be achondroplasia dwarves? A) 9/16 B) 3/4 C) 100% D) 2/3 E) not enough info to tell. The presence of short stature and unusual proportions is an example of which of the following phenomena? A) epistasis B) codominance C) pleiotropy D) incomplete dominance E) none of the above If white flowers are recessive to purple flowers, if two white-flowered peas mate, what proportion of the offspring would be white-flowered? A) 0 B) 1.0 C) 3/16 D) 9/16 E) can't tell What type of a variable is a person's shoe size? A) An attribute B) Discontinuous Measurable C) A Rank D) Continuous Measurable

Explanation / Answer

Ans. 14. Genotype of the dwarf male = Aa          ; gametes produced by male = A, a

Genotype of the dwarf female = Aa        ; gametes produced by female = A, a

Now, male (Aa) x female (Aa)

            [A, a]male x [A, a]female = AA, Aa, Aa, aa - total number of progeny is 4.

Homozygous AA fetus does not services. Thus, total number of surviving progeny = 3.

Number of surviving achondroplasic dwarves = 2

Proportion of surviving dwarf = number of surviving dwarves / total number of surviving progeny

                                                = 2/3

Thus, correct option. D. 2/3    

Ans. 15. E. None of the above. Option A: Incorrect. Allele A is dominant which presence causes dwarfism

Option B and D- Incorrect. Achondroplasia exhibits the inheritance pattern of complete dominance.

Option. C. Incorrect- Pleiotropy refers to a condition where one gene controls two or more unrelated traits/character. Here, achondroplasia alleles control one trait only.

Ans. 16. Let the dominant allele = P, for purple flower

                  The recessive allele = p for white flower in homozygous condition.

Genotype of white flower = pp   ; gametes produced = p

Now, p (male) x p (female) = pp             ; total number of F1 progeny =1

Proportion of white-flower = number of white flower / total number of F1 progeny

                                                = 1/1 = 1

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