You are given a parallel-plate capacitor with square plates ofarea A, and separa

Question

You are given a parallel-plate capacitor with square plates ofarea A, and separation d, in a vacuum. Each plate has a charge q.There is no battery nor any other source of charge connected to theplates. If the plate area is doubled, explain what happensto: a) The surface charge density (The exercise goes further and the surface charge density isthe only part I dont actually understand) You are given a parallel-plate capacitor with square plates ofarea A, and separation d, in a vacuum. Each plate has a charge q.There is no battery nor any other source of charge connected to theplates. If the plate area is doubled, explain what happensto: a) The surface charge density (The exercise goes further and the surface charge density isthe only part I dont actually understand)

Explanation / Answer

         = q / A      if area of the plates are doubled       A = 2A       then the surface charge densitydecreases to half of its value

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