So that\'s the Joule-Thomson coefficient. (Also forgot to putthat the partial de

Question

So that's the Joule-Thomson coefficient. (Also forgot to putthat the partial deriv. on left should have an H subscriptindicating constant enthalpy H) Problem says that the equation of state can be expressedas p = kT[n + B(T)n^2 + ...] where n is particle density (n = N/V). When at low pressure, where Bn is small (Bn, notBn^2), and all higher terms in the above expansion arenegligible, it can be shown that the Joule-Thomson coefficient isapproximately: So basically, the V gets replaced by NB? I think? How do Iarrive at this approximated result?? Thank you

Explanation / Answer

Oh by the way, I tried doing the binomial series approximationwhere (1 + x)^(-1) ˜ 1 - x + x^2 ... and it sort of started lookingright but had a minus sign and just not right.

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