The mean distance of an asteroid from the Sun is 2.71 timesthat of Earth from th

Question

The mean distance of an asteroid from the Sun is 2.71 timesthat of Earth from the Sun. From Kepler's law of periods, calculatethe number of years required for the asteroid to make onerevolution around the Sun. Pls provide correctunits...
the tolerance is+/-2% The mean distance of an asteroid from the Sun is 2.71 timesthat of Earth from the Sun. From Kepler's law of periods, calculatethe number of years required for the asteroid to make onerevolution around the Sun. Pls provide correctunits...
the tolerance is+/-2%

Explanation / Answer

given the distance of an asteroid is 2.71 times that of earth from the sun let the distance of the earth from the sun = R then the distance of the asteroid from the sun is =2.71*R the time period of the earth si = T = 1 year let the time period of the asteroid is T ' then wehave                         T' / T = ( 2.71R / R )3/2                           T ' = T ( 2.71)3/2 =4.46years     ( earth years)                           T ' = T ( 2.71)3/2 =4.46years     ( earth years)

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