A serum globulin sample has a sedimentation coefficient s of 7.1 * 10 -13 second

Question

A serum globulin sample has a sedimentation coefficient s of 7.1 * 10 -13 seconds (7.1 S in Svedberg (A) units where 1S = 10 – 13 seconds) in water density 0.988 g cm-3 at 20C, a molecular weight M of 5.12 * 102 kDa (5,12 * 105 g mol-1), and a specific volume vs of 0.749 cm3 g-1.

How far will the protein boundary move in 30 min if the speed of the centrifuge is 60,000 rpm (revolutions per minute) and the initial boundary is 6.5 cm from the axis of rotation; then Calculate the diffusion constant D of the globulin at 20C, and hence obtain the root mean square distance of diffusive broadening that is undergone by the protein boundary in the 30 min sedimentation and from your answers in the first part, explain whether or not the broadening represents a problem in carrying out the sedimentation described in part 1.

Explanation / Answer

Answer:

Diffusion coefficient (D) = (1/f)kT

Where f= frictional coefficient

k= Boltzman constant and T= absolute temperature

x2 = qiDtx2 - mean-square displacement i.e the mean distance from the starting point

t= diffused time
qi - numerical constant

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