The space shuttle is in a 330 mile high orbit. What are the shuttle\'sorbital pe
ID: 1764028 • Letter: T
Question
The space shuttle is in a 330 mile high orbit. What are the shuttle'sorbital period, in minutes, and its speed? Ts min vs m/s(a) What isthe free-fall acceleration at the surface of the sun?
m/s2
(b) Billions of years from now, the sun will become a red giantstar and its radius will swell to the size of the earth's orbit.Assuming its mass doesn't change, what will be the free-fallacceleration on the surface at that time?
m/s2
(a) What isthe free-fall acceleration at the surface of the sun?
m/s2
(b) Billions of years from now, the sun will become a red giantstar and its radius will swell to the size of the earth's orbit.Assuming its mass doesn't change, what will be the free-fallacceleration on the surface at that time?
m/s2 Ts min vs m/s
Explanation / Answer
Given : Height ( h ) = 330 mile = 330 * 1.6 km = 528 km Universal gravitational constant ( G ) =6.67 * 10-11 N.m2 / kg2 Mass of the earth ( M ) = 6 * 1024 kg g = 9.8 m/s2 Mean radius of earth ( R ) = 6.4 * 106m orbital period ( T ) = 2 ( R + h ) 3/2/ GM = ----- min Velocity ( V ) = GM / r => R g /(R+h) = ----- m/s b ) g = GM/ R2 ( R ) = 7 * 105 km ( R ) = 7 * 105 km Accleration due to gravity on the suface of the sun ( g ) =274 m/s2 c ) Mass of the sun ( M ) = 2*1030 kg radius will swell to the size of the earth'sorbit.=( R ) = 6.4 * 106 m accleration ( g ) = GM /R2 = ------- m/s2 Solve it I hope it helps you Solve it I hope it helps youRelated Questions
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