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1. The potential energy stored in the compressedspring of a dart gun, with a spr

ID: 1763700 • Letter: 1

Question

1. The potential energy stored in the compressedspring of a dart gun, with a spring constant of 60.00 N/m, is 1.260J. Find by how much is the spring is compressed.
2. A 0.170 kg dart is firedstraight up. Find the vertical distance the dart travels from itsposition when the spring is compressed to its highestposition.
3. The same dart isnow fired horizontally from a height of 3.90 m. The dart remains incontact until the spring reaches its equilibrium position. Find thehorizontal velocity of the dart at thattime.
4.
2. A 0.170 kg dart is firedstraight up. Find the vertical distance the dart travels from itsposition when the spring is compressed to its highestposition.
3. The same dart isnow fired horizontally from a height of 3.90 m. The dart remains incontact until the spring reaches its equilibrium position. Find thehorizontal velocity of the dart at thattime.
4. 2. A 0.170 kg dart is firedstraight up. Find the vertical distance the dart travels from itsposition when the spring is compressed to its highestposition.
3. The same dart isnow fired horizontally from a height of 3.90 m. The dart remains incontact until the spring reaches its equilibrium position. Find thehorizontal velocity of the dart at thattime.
4.

Explanation / Answer

1) The potential energy stored in the compressedspring of a dart guln is                   U = (1/2)kx2    The compresssed distance is                    x = (2U/k) Here U = 1.260 J            k= 60,000 N/m 2) From the law of conservation of the energy ,we have                     mgh =U The vertical distance is                    h = U/(mg) Here m = 0.170 kg Substitute the values. Note: Please submit one question per post.    The compresssed distance is                    x = (2U/k) Here U = 1.260 J            k= 60,000 N/m 2) From the law of conservation of the energy ,we have                     mgh =U The vertical distance is                    h = U/(mg) Here m = 0.170 kg Substitute the values. Note: Please submit one question per post.