A cannon ball is fired horizontally from the top of a hill 500mabove a level val

Question

A cannon ball is fired horizontally from the top of a hill 500mabove a level valley. The initial velocity of the cannon ball is200m/s. Find:
a) The time the ball is in the air before hitting the groundin the valley. b) The horizontal distance from the cannon to the point theball hits the ground. c) The magnitude and direction of the velocity of the balljust before it hits the ground.

a) The time the ball is in the air before hitting the groundin the valley. b) The horizontal distance from the cannon to the point theball hits the ground. c) The magnitude and direction of the velocity of the balljust before it hits the ground.

Explanation / Answer

a) let the time be t, we have: h = 500m = (1/2)gt2 t = [2*500m/9.8m/s2] = 10.10 s b) vx = 200m/s distance d = vx t = 200m/s*10.10s = 2020.31 m c) vy = gt = 9.8m/s2 * 10.10s =98.98m/s magtitude of speed v = [(vx)2 +(vy)2] =[(200m/s)2+(98.98m/s)2]=223.15m/s angle = tan-1 (vy/vx)= tan-1 (98.98m/s / 200m/s) =26.33 0 t = [2*500m/9.8m/s2] = 10.10 s b) vx = 200m/s distance d = vx t = 200m/s*10.10s = 2020.31 m c) vy = gt = 9.8m/s2 * 10.10s =98.98m/s magtitude of speed v = [(vx)2 +(vy)2] =[(200m/s)2+(98.98m/s)2]=223.15m/s angle = tan-1 (vy/vx)= tan-1 (98.98m/s / 200m/s) =26.33 0

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