According to Hooke\'s Law, the force of a spring is F = -kx(not kx 2 ). If this

Question

According to Hooke's Law, the force of a spring is F = -kx(not kx2). If this is true, the spring constant (k) should =-mv2/x : -0.5kx = 0.5mv2 k =  -mv2/x This would change the data significantly. Is my reasoningcorrect? According to Hooke's Law, the force of a spring is F = -kx(not kx2). If this is true, the spring constant (k) should =-mv2/x : -0.5kx = 0.5mv2 k =  -mv2/x This would change the data significantly. Is my reasoningcorrect? k =  -mv2/x This would change the data significantly. Is my reasoningcorrect?

Explanation / Answer

Potential energy = kinetic energy ( 1/ 2) k x ^ 2 = ( 1/ 2) m v ^ 2                 k= mv^2 / x^ 2               Or work W = Fx              = [ kx+ 0 ] / 2 * x = ( 1/ 2) k x^ 2 this is equal to kinetic energy ( 1/ 2) k x ^ 2 = ( 1/ 2) m v ^ 2                 k= mv^2 / x^ 2 ( 1/ 2) k x ^ 2 = ( 1/ 2) m v ^ 2                 k= mv^2 / x^ 2

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