a man standing on top of a bridge 95 yards high fired a bulletvertically upwards

Question

a man standing on top of a bridge 95 yards high fired a bulletvertically upwards and reaches the height of 4560 yards a. find the time it takes to reach maximum height b. its final velocity when it hits the ground c. tis total work d. what is the potential engery of the bullet in its maximumheight a man standing on top of a bridge 95 yards high fired a bulletvertically upwards and reaches the height of 4560 yards a. find the time it takes to reach maximum height b. its final velocity when it hits the ground c. tis total work d. what is the potential engery of the bullet in its maximumheight

Explanation / Answer

(a)   max height from point of projection, y =4560 - 95 = 4465 yards = 4465 X 0.914 m = 4081.01 m         velocity ofprojection, u = ( 2gy) = 282.82 m/s         time taken to reachmaximum height, t = u / g = 282.82 / 9.8 = 28.86 s (b)    height of the bridge, h = 95 yards = 95X 0.914 = 86.83 m          s = ut + (1/2 ) at2        -h = u t - ( 1/2)gt2         - 86.83 = 282.82 t- 4.9 t2                 4.9 t2 - 282.82 t - 86.83 = 0                   by solving , t = 58.02 s (c)   Work done by gravitational force, W = (F)(S) = Mgh = ( 9.8 ) ( 86.83 ) M = 850.9M joules                                                                                                                              ( here M = mass of the bullet) (d) max height from the ground - 4560 yards = 4560 X0.914 = 4167.84 m Potential energy at max height = mg ( max height fromground) = (9.8) (4167.84) M                                                                                                   =40844.8 M joules                          4.9 t2 - 282.82 t - 86.83 = 0                   by solving , t = 58.02 s (c)   Work done by gravitational force, W = (F)(S) = Mgh = ( 9.8 ) ( 86.83 ) M = 850.9M joules                                                                                                                              ( here M = mass of the bullet) (d) max height from the ground - 4560 yards = 4560 X0.914 = 4167.84 m Potential energy at max height = mg ( max height fromground) = (9.8) (4167.84) M                                                                                                   =40844.8 M joules         

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.