A Chevrolet Corvette convertible can brake to a stop from aspeed of 60.0 mi/h in

Question

A Chevrolet Corvette convertible can brake to a stop from aspeed of 60.0 mi/h in a distance of 123 ft on a level roadway. Whatis its stopping distance on a roadway sloping downward at an angleof 40.0°?
- there's just a key concept that I am notunderstanding. Thanks for helping.
A Chevrolet Corvette convertible can brake to a stop from aspeed of 60.0 mi/h in a distance of 123 ft on a level roadway. Whatis its stopping distance on a roadway sloping downward at an angleof 40.0°?
- there's just a key concept that I am notunderstanding. Thanks for helping.

Explanation / Answer

The accleration of the car sloping downward is          a = gsin            = 9.8 *sin40 = 6.29 m/s2 The time taken by the car to travell a distance 123 ftis             t = d /v = 123 ft / 60 mi /h                                     = 37.49m/26.81m/s                                     = 1.398 s In this time the car car travell a distance on the inclinedplane is                 S = vt + 0.5 * a * t2                    = 37.49 + 0.5 * 6.29 * 1.398 *1.398                    = 37.49 m+ 6.147 m                    = 43.637 m                    = 143.17 ft

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.