OSCAR THE OTTER IS HAVING FUN SLIDING DOWN A MUDBANK. OSCAR HAS A MASS M = 10.91

Question

OSCAR THE OTTER IS HAVING FUN SLIDING DOWN A MUDBANK. OSCAR HAS A MASS M = 10.91 KG. THE LENGTH OF THEMUD BANK IS L = 5.52 METERS. THE COEFFICIENT OF KINETICFRICTION BETWEEN OSCAR AND THE BANK IS MU = .338 THE ANGLE THE MUDBANK MAKES W.R.T. THE HORIZONTAL IS THETA = 30.1 DEGREES. AFTERWORK, OSCAR DECIDED TO CALCULATE WHAT HE COULD ABOUT THE DAYS'SFUN. HE FOUND THAT TAKING THE +X AXIS TO LIE ALONG THE BANKAND POINTING DOWN HILL SEEMED TO MAKE HIS SOLUTIONS A LITTLEEASIER. (A) CALCULATE OSCAR'S ACCELERATION DOWN HILL. (the answer is suppose to be 2.05 m/s2 but I cant get theright answer when working it out.) OSCAR THE OTTER IS HAVING FUN SLIDING DOWN A MUDBANK. OSCAR HAS A MASS M = 10.91 KG. THE LENGTH OF THEMUD BANK IS L = 5.52 METERS. THE COEFFICIENT OF KINETICFRICTION BETWEEN OSCAR AND THE BANK IS MU = .338 THE ANGLE THE MUDBANK MAKES W.R.T. THE HORIZONTAL IS THETA = 30.1 DEGREES. AFTERWORK, OSCAR DECIDED TO CALCULATE WHAT HE COULD ABOUT THE DAYS'SFUN. HE FOUND THAT TAKING THE +X AXIS TO LIE ALONG THE BANKAND POINTING DOWN HILL SEEMED TO MAKE HIS SOLUTIONS A LITTLEEASIER. (A) CALCULATE OSCAR'S ACCELERATION DOWN HILL. (the answer is suppose to be 2.05 m/s2 but I cant get theright answer when working it out.)

Explanation / Answer

The acceleration of the OSCAR during down hill is                F = mgsin - fk                 ma= mgsin - kmgcos a = g(sin - kcos)          = 9.8(sin30.1 - 0.338cos30.1)          =9.8(0.50-0.292)          =9.8*0.207          =2.04 m/s2

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