A brass rod is in thermal contact with a constant-temperaturereservoir at 140 ce

Question

A brass rod is in thermal contact with a constant-temperaturereservoir at 140 celsius at one end and a constant-temperaturereservoir at 20 celsius at the other end. (a) Compute the total change in entropy of the rod-reservoirssystem when 5070J of energy is conducted through the rod, from onereservoir to the other. ___________ J/K (b) Does the entropy of the rod change in the process? Yes orNo? A brass rod is in thermal contact with a constant-temperaturereservoir at 140 celsius at one end and a constant-temperaturereservoir at 20 celsius at the other end. (a) Compute the total change in entropy of the rod-reservoirssystem when 5070J of energy is conducted through the rod, from onereservoir to the other. ___________ J/K (b) Does the entropy of the rod change in the process? Yes orNo?

Explanation / Answer

Temperature of Hot reservoir T = 140 oC = 140 + 273 =413 K Temperature of cole reservoir T ' = 20 oC = 20 +273 = 293 K Energy conducted Q = 5070 J the total change in entropy of the rod-reservoirs system S = Q / dT                                                                                          = 42.25 J / K (b). Entropy of the rod changes in this process

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.