a.) If the electric field at a point in space has a magnitudeof 300 volts/meter,

Question

a.) If the electric field at a point in space has a magnitudeof 300 volts/meter, about how far apart are the equipotentialsurfaces that differ by 10 volts? b.) Two parallel conducting plates are separated by 0.60 cm.If the potential difference between the plates is 90V, what is themagnitude of the electric vector midway between the plates? a.) If the electric field at a point in space has a magnitudeof 300 volts/meter, about how far apart are the equipotentialsurfaces that differ by 10 volts? b.) Two parallel conducting plates are separated by 0.60 cm.If the potential difference between the plates is 90V, what is themagnitude of the electric vector midway between the plates?

Explanation / Answer

a.)The electric field is given by V = E * d or d = (V/E) E = 300 volts/meter and V = 10 volts b.)The magnitude of the electric vector midway between theplates is V1 = E1 * d1 or E1 = (V1/d1) V1 = 90 volts and d1 = (d/2) = (0.60/2)cm = 0.30 cm = 0.30 * 10-2 m or E1 = (V1/d1) V1 = 90 volts and d1 = (d/2) = (0.60/2)cm = 0.30 cm = 0.30 * 10-2 m

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