I cant figure out this problem for some reason.... the answerhere in cramster us

Question

I cant figure out this problem for some reason.... the answerhere in cramster uses the wrong units and doesn't give thecomponents (i and j)   *** the picture for the problemcan be found in cramster textbook help prob 14. Three charged particles are at the corners of anequilateral triangle as shown in the figure below (q =4.00 µC, L =0.500 m). (a) Calculate the electric field at theposition of charge q due to the 7.00 µC and -4.00µC charges.
........... kN/Ci + ....... kN/Cj

(b) Use your answer to part (a) to determine the force on chargeq.
mNi + mN j I cant figure out this problem for some reason.... the answerhere in cramster uses the wrong units and doesn't give thecomponents (i and j)   *** the picture for the problemcan be found in cramster textbook help prob 14. Three charged particles are at the corners of anequilateral triangle as shown in the figure below (q =4.00 µC, L =0.500 m). (a) Calculate the electric field at theposition of charge q due to the 7.00 µC and -4.00µC charges.
........... kN/Ci + ....... kN/Cj

(b) Use your answer to part (a) to determine the force on chargeq.
mNi + mN j (a) Calculate the electric field at theposition of charge q due to the 7.00 µC and -4.00µC charges.
........... kN/Ci + ....... kN/Cj

(b) Use your answer to part (a) to determine the force on chargeq.
mNi + mN j

Explanation / Answer

Let       q1 = -4 Cand
      q2 = 7C
       q = 4.00 µC       L = 0.500 m        ke =1/4o Electric field at charge q due to q1 is          E1=( keq1 / L2 ) i
Electric field direction at q is right.
Electric field at charge q due to q2 is          E2= ( keq2 / L2) (-cos(60) i -sin(60) j)
Charge q2 is positive, the fielddirection at q is left and down, away from q2.
         E = E1 + E2             = ( keq1 / L2 ) i + (keq2 / L2) (-cos(60) i - sin(60)j) The force on charge q is          F = Eq            = q* (( keq1 /L2 ) i + ( keq2 / L2)(-cos(60) i - sin(60) j)) Substitute values.


Substitute values.

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