The efficiency of a particular car engine is 22% when the engine does8.8 kJ of w

Question

The efficiency of a particular car engine is 22% when the engine does8.8 kJ of work per cycle. Assume theprocess is reversible. (a) What is the energy the engine gains percycle as heat Qgain fromthe fuel combustion?
1 kJ

(b) What is the energy the engine loses per cycle as heatQlost?
2 kJ

(c) If a tune-up increases the efficiency to 27%, what isQgain at the same workvalue?
3 kJ

(d) If a tune-up increases the efficiency to 27%, what isQlost at the same workvalue?
4 kJ (a) What is the energy the engine gains percycle as heat Qgain fromthe fuel combustion?
1 kJ

(b) What is the energy the engine loses per cycle as heatQlost?
2 kJ

(c) If a tune-up increases the efficiency to 27%, what isQgain at the same workvalue?
3 kJ

(d) If a tune-up increases the efficiency to 27%, what isQlost at the same workvalue?
4 kJ

Explanation / Answer

a) Work = efficiency * Qgain
      8.8kJ = (0.22)Qgain
        Qgain = 8.8kJ/0.22
               = 40.0 kJ

b)        Qlost =Qgain - W
                  = 40.0kJ - 8.8kJ
                  = 31.2 kJ

  c)Work = efficiency * Qgain
      8.8kJ = (0.27)Qgain
        Qgain = 8.8kJ/0.27
               = 32.6 kJ

d)      Qlost =Qgain - W
                  = 32.6kJ - 8.8kJ
                  = 23.8 kJ

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