a massless rope passes over massles pulley attached toceiling. On one ed is stud

Question

a massless rope passes over massles pulley attached toceiling. On one ed is student A, mass 70 kg, who is at reston floor. Opposite end of rope held by Student B, mass 60 kgwho is suspended at rest above floor. What is magnitude of force exerted by floor on Student A Student B climbs up rope at constant acceleration of 0.25 m/ssquared with respect to floor What is tension in rope whilbe Student B is accelerating Is Student A pulled upward off floor while B isaccelerating? What minimum acceleration must Student B climb up rope to liftStudent A upward off floor? a massless rope passes over massles pulley attached toceiling. On one ed is student A, mass 70 kg, who is at reston floor. Opposite end of rope held by Student B, mass 60 kgwho is suspended at rest above floor. What is magnitude of force exerted by floor on Student A Student B climbs up rope at constant acceleration of 0.25 m/ssquared with respect to floor What is tension in rope whilbe Student B is accelerating Is Student A pulled upward off floor while B isaccelerating? What minimum acceleration must Student B climb up rope to liftStudent A upward off floor?

Explanation / Answer

a)Student B has a weight due to gravitydownwards(mg) and the tension in the rope F.Student A also has thesame, and the tension in the rope for each is the same, so themagnitude of the force exerted by the floor on student A is: -- F = mg F = (70)(9.8) ---> mass of StudentA F = 686 N --
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b)Given that he is accelerating upwards: -- F = ma = T - mg 60(0.25m/s^2) = T - 60(9.8m/s^2) --->using mass of Student B
T = 603N
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c)No, because the tension from Student B as he is accelerating, isless than the tension from Student A. 603N < 686N
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d) ma = T - mg.
(60)a = 686 - (60)(9.8m/s^2)
a = 1.6 m/s^2
-- -- Hope this helps.

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