A 3.0 kg object has the following two forces acting onit, F 1 = (16i + 12j) N F

Question

A 3.0 kg object has the following two forces acting onit, F1 = (16i + 12j) N F2 = (-10i + 22j) N If the object is initially at rest, determine its velocity vat t = 3.0s I dont know what to do with this. We dont go overanything in class. thanks for your help A 3.0 kg object has the following two forces acting onit, F1 = (16i + 12j) N F2 = (-10i + 22j) N If the object is initially at rest, determine its velocity vat t = 3.0s I dont know what to do with this. We dont go overanything in class. thanks for your help

Explanation / Answer

A 3.0 kg object has the following two forces acting onit, F1 = (16i + 12j) N F2 = (-10i + 22j) N If the object is initially at rest, determine its velocity vat t = 3.0s I dont know what to do with this. We dont go overanything in class. thanks for your help
the resultant force= F1+F2=(16i + 12j) N+(-10i + 22j) N=6i+34j
magnitude of the force= 6*6+34*34=34.52N
acceleration due to the force= force/mass=34.52/3=11.50m/sec2
velocity at t= 3.0sec
v=u+at=0+11.5*3=34.5m/sec

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