G)What is the total electric flux through all faces of thecube? The cube in thef
ID: 1760518 • Letter: G
Question
G)What is the total electric flux through all faces of thecube? The cube in thefigure has sides of length L=10.0 {rm cm}. The electric field is uniform, has a magnitudeE=4.00 times 10^{3} {rm N}/{rm C}, and is parallel to the xy-plane at anangle of 36.9 measured from the + x - {rm axis} toward the + y - {rm axis}. (For each face of the cube choose the outwardpointing normal, away from the cube's center.) yf_Figure_22_32.jpg A)What is the electric flux through the cube face S_1? B)What is the electric flux through the cube face S_2? C)What is the electric flux through the cube face S_3? D)What is the electric flux through the cube face S_4? E)What is the electric flux through the cube face S_5? F)What is the electric flux through the cube face S_6? G)What is the total electric flux through all faces of thecube?Explanation / Answer
given E = 4*103 N/C Area A = (10*10-2m)(10*10-2m) =0.01m2 is the angle made by the electric field with the normalto the surface.A) For the surface S1 normal to the surface is -yaxis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore angle made by the electric fieldwith the y-axis is 90o-36.9o = 53.1o therefore the angle made by the electric field with the normalto the surface S1 is 180o + 53.1o= 233.1o Then 1 =(4*103 N/C)(0.01m2)(cos233.1o) =-24Nm2/C B) For the surface S1 normal to the surface isz axis. as the elcetric field is parallel to the XY plane thereforethe angle made by the electric field with the z-axis is90o therefore the angle made by the electric field with the normalto the surface S2 is 90o Then 2 =(4*103 N/C)(0.01m2)(cos90o) =0Nm2/C
C) For the surface S3 normal to the surface isy axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore angle made by the electric fieldwith the y-axis is90o-36.9o = 53.1o therefore the angle made by the electric field with the normalto the surface S3 is 53.1o Then 3 =(4*103 N/C)(0.01m2)(cos53.1o) =24Nm2/C
D) For the surface S4 normal to thesurface is z axis. as the elcetric field is parallel to the XY plane thereforethe angle made by the electric field with the z-axis is90o therefore the angle made by the electric field with the normalto the surface S4 is 90o Then 4 =(4*103 N/C)(0.01m2)(cos90o) =0Nm2/C
E) For the surface S5 normal to the surface isx axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S5is 36.9o Then 5 =(4*103 N/C)(0.01m2)(cos36.9o) =32Nm2/C
F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C B) For the surface S1 normal to the surface isz axis. as the elcetric field is parallel to the XY plane thereforethe angle made by the electric field with the z-axis is90o therefore the angle made by the electric field with the normalto the surface S2 is 90o Then 2 =(4*103 N/C)(0.01m2)(cos90o) =0Nm2/C
C) For the surface S3 normal to the surface isy axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore angle made by the electric fieldwith the y-axis is90o-36.9o = 53.1o therefore the angle made by the electric field with the normalto the surface S3 is 53.1o Then 3 =(4*103 N/C)(0.01m2)(cos53.1o) =24Nm2/C
D) For the surface S4 normal to thesurface is z axis. as the elcetric field is parallel to the XY plane thereforethe angle made by the electric field with the z-axis is90o therefore the angle made by the electric field with the normalto the surface S4 is 90o Then 4 =(4*103 N/C)(0.01m2)(cos90o) =0Nm2/C
E) For the surface S5 normal to the surface isx axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S5is 36.9o Then 5 =(4*103 N/C)(0.01m2)(cos36.9o) =32Nm2/C
F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C C) For the surface S3 normal to the surface isy axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore angle made by the electric fieldwith the y-axis is90o-36.9o = 53.1o therefore the angle made by the electric field with the normalto the surface S3 is 53.1o Then 3 =(4*103 N/C)(0.01m2)(cos53.1o) =24Nm2/C
D) For the surface S4 normal to thesurface is z axis. as the elcetric field is parallel to the XY plane thereforethe angle made by the electric field with the z-axis is90o therefore the angle made by the electric field with the normalto the surface S4 is 90o Then 4 =(4*103 N/C)(0.01m2)(cos90o) =0Nm2/C
E) For the surface S5 normal to the surface isx axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S5is 36.9o Then 5 =(4*103 N/C)(0.01m2)(cos36.9o) =32Nm2/C
F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C D) For the surface S4 normal to thesurface is z axis. as the elcetric field is parallel to the XY plane thereforethe angle made by the electric field with the z-axis is90o therefore the angle made by the electric field with the normalto the surface S4 is 90o Then 4 =(4*103 N/C)(0.01m2)(cos90o) =0Nm2/C
E) For the surface S5 normal to the surface isx axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S5is 36.9o Then 5 =(4*103 N/C)(0.01m2)(cos36.9o) =32Nm2/C
F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C E) For the surface S5 normal to the surface isx axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S5is 36.9o Then 5 =(4*103 N/C)(0.01m2)(cos36.9o) =32Nm2/C
F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C Then 5 =(4*103 N/C)(0.01m2)(cos36.9o) =32Nm2/C
F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C F) For the surface S6 normal to the surface is-x axis. here the electric field makes an angle 36.9o withthe positive x - axis. therefore the angle made by theelectric field with the normal to the surface S6 is180o + 36.9o =216.9o Then 6 =(4*103 N/C)(0.01m2)(cos216.9o) =-32Nm2/C
G) Total electric flux is = 1+ 2 + 3+ 4 + 5+ 6 = 0Nm2/C = 0Nm2/C
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.