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At the instant the traffic light turns green, and automobilethat has been wating

ID: 1760145 • Letter: A

Question

At the instant the traffic light turns green, and automobilethat has been wating at an intersection starts ahead with aconstant accelereation of 2.70 m/s^2. At the same instant, a truck,traveling with a constant speed of 15.5m/s overtakes and passes theautomobile. How far beyond its starting pt does the automobile overtakethe truck? please show work for lifesaver. thanks At the instant the traffic light turns green, and automobilethat has been wating at an intersection starts ahead with aconstant accelereation of 2.70 m/s^2. At the same instant, a truck,traveling with a constant speed of 15.5m/s overtakes and passes theautomobile. How far beyond its starting pt does the automobile overtakethe truck? please show work for lifesaver. thanks

Explanation / Answer

      Initial velocity ofautomobile, u = 0        acceleration ofautomobile, a = 2.70 m/s^2      constant velocity of truck, v = 15.5m/s       Let both of them meet eachother after travelling a distance 'S' in a time 't'              distance travelled by automobile in t seconds , S = ut + (1/2)at2                                                                                        = (1/2) * 2.7 * t2 ..........(1)               distance travelled by truck, S = v t =15.5 t  .................(2)        by equating (1) and(2)                                                  15.5 t =  (1/2) * 2.7 * t2                                  by solving , t = 11.48 s          distanceat which they overtake , S = 15.5 t = 15.5 * 11.48 = 177. 96m                                                                                        = (1/2) * 2.7 * t2 ..........(1)               distance travelled by truck, S = v t =15.5 t  .................(2)        by equating (1) and(2)                                                  15.5 t =  (1/2) * 2.7 * t2                                  by solving , t = 11.48 s          distanceat which they overtake , S = 15.5 t = 15.5 * 11.48 = 177. 96m                                  by solving , t = 11.48 s          distanceat which they overtake , S = 15.5 t = 15.5 * 11.48 = 177. 96m