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This is a 2 part question, and I got part A correct, but cannot getpart B correc

ID: 1759588 • Letter: T

Question

This is a 2 part question, and I got part A correct, but cannot getpart B correct.
My question reads: "The helicopter view in the figure belowshows two people pulling on a stubborn mule. Assume F1 is 120 N at60 degrees and F2 is 80 N at 75 degrees. The forces aremeasure in units of newtons (N).
Part A (which I got correct): Find the single force that isequivalent to the two forces shown: Magnitude= 186 N Direction= 78 degrees (counterclockwise from the+x-axis)
Part B (which I got INcorrect): Find the force that a thirdperson would have to exert on the mule to make the net force equalto zero. Magnitude= ? Direction= ? (counterclockwise from the +x-axis)
My question reads: "The helicopter view in the figure belowshows two people pulling on a stubborn mule. Assume F1 is 120 N at60 degrees and F2 is 80 N at 75 degrees. The forces aremeasure in units of newtons (N).
Part A (which I got correct): Find the single force that isequivalent to the two forces shown: Magnitude= 186 N Direction= 78 degrees (counterclockwise from the+x-axis)
Part B (which I got INcorrect): Find the force that a thirdperson would have to exert on the mule to make the net force equalto zero. Magnitude= ? Direction= ? (counterclockwise from the +x-axis)

Explanation / Answer


   we are given that    F1 = 120 N and    F2 = 80.0 N    F1x = F1cos75o          = ........N    F2x = - F2cos75o          = ........N    F2y = F2sin75o          =......... N    the resultanr force will be    R = [(Fx2) + (Fy2)]        = ....... N    direction will be     = tan-1(Fy /Fx)       = ......o (b)    to get the zero net force on the mule the aboveforce must be cancelled by a force equal in    magnitude and oppositely directed sothat the required force will be R and the direction will be180o +
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