This is a 2 part question, and I got part A correct, but cannot getpart B correc
ID: 1759588 • Letter: T
Question
This is a 2 part question, and I got part A correct, but cannot getpart B correct.My question reads: "The helicopter view in the figure belowshows two people pulling on a stubborn mule. Assume F1 is 120 N at60 degrees and F2 is 80 N at 75 degrees. The forces aremeasure in units of newtons (N).
Part A (which I got correct): Find the single force that isequivalent to the two forces shown: Magnitude= 186 N Direction= 78 degrees (counterclockwise from the+x-axis)
Part B (which I got INcorrect): Find the force that a thirdperson would have to exert on the mule to make the net force equalto zero. Magnitude= ? Direction= ? (counterclockwise from the +x-axis)
My question reads: "The helicopter view in the figure belowshows two people pulling on a stubborn mule. Assume F1 is 120 N at60 degrees and F2 is 80 N at 75 degrees. The forces aremeasure in units of newtons (N).
Part A (which I got correct): Find the single force that isequivalent to the two forces shown: Magnitude= 186 N Direction= 78 degrees (counterclockwise from the+x-axis)
Part B (which I got INcorrect): Find the force that a thirdperson would have to exert on the mule to make the net force equalto zero. Magnitude= ? Direction= ? (counterclockwise from the +x-axis)
Explanation / Answer
we are given that F1 = 120 N and F2 = 80.0 N F1x = F1cos75o = ........N F2x = - F2cos75o = ........N F2y = F2sin75o =......... N the resultanr force will be R = [(Fx2) + (Fy2)] = ....... N direction will be = tan-1(Fy /Fx) = ......o (b) to get the zero net force on the mule the aboveforce must be cancelled by a force equal in magnitude and oppositely directed sothat the required force will be R and the direction will be180o +
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