I am done with this question, but I would like to know whatthe answer is... The

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I am done with this question, but I would like to know whatthe answer is... The even answers are not in the back of the book,and I would like to know if I got the correct answer. "A force vector with a magnitude of 50 lb that is in the thirdquadrant with an x component whose magnitude is 40 lb. Rewrite thisvector in terms of its magnitude and angle (counterclockwise fromthe +x direction)." I got a magnitude of 50 lb (given) and =37o.Is this correct? Someone please do the problem and check myanswers. Thanks! I am done with this question, but I would like to know whatthe answer is... The even answers are not in the back of the book,and I would like to know if I got the correct answer. "A force vector with a magnitude of 50 lb that is in the thirdquadrant with an x component whose magnitude is 40 lb. Rewrite thisvector in terms of its magnitude and angle (counterclockwise fromthe +x direction)." I got a magnitude of 50 lb (given) and =37o.Is this correct? Someone please do the problem and check myanswers. Thanks!

Explanation / Answer

x component of the vector is 40 lb. Magnitude of the vector is 50 lb. Then 40 lb = (50lb)(cos)               = 36.9o                      = 180 + 36.9o = 216.9o above the positive xdirection

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