The body resistance of an average person is approximately 2.5M from palm to palm

Question

The body resistance of an average person is approximately 2.5M from palm to palm. Suppose you are walking along aconvention center and accidentally grasps the terminals of a 14 kVpower supply
a) What will be the current through your body if the internalresistance of said power supply is 2k
b) What is the power dissipated in your body?
c) If the power supply is to be made safe by increasing itsinternal resistance, what should the internal resistance be for themaximum current that would pass through you be 1.0 mA or less

Explanation / Answer

Given : b )   Resitance ( R ) = 2.5 M = 2.5 *106    Voltage ( V ) = 14 kV = 14 * 103V Power ( P ) = V2/ R                    = ( 14 * 103 V) 2 / ( 2.5 * 106 )                    = ------ W Solve it I hope it helps you

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