Consider three identical metal spheres, A , B , and C . Sphere A carries a charg
ID: 1759284 • Letter: C
Question
Consider three identical metal spheres, A,B, and C. SphereA carries a charge of –2.0 µC; sphereB carries a charge of –6.0 µC; andsphere C carries a charge of +5.0 µC.Spheres A and B are touchedtogether and then separated. Spheres B andC are then touched and separated. Does sphereC end up with an excess or a deficiency ofelectrons and how many electrons is it? Consider three identical metal spheres, A,B, and C. SphereA carries a charge of –2.0 µC; sphereB carries a charge of –6.0 µC; andsphere C carries a charge of +5.0 µC.Spheres A and B are touchedtogether and then separated. Spheres B andC are then touched and separated. Does sphereC end up with an excess or a deficiency ofelectrons and how many electrons is it?
Consider three identical metal spheres, A,B, and C. SphereA carries a charge of –2.0 µC; sphereB carries a charge of –6.0 µC; andsphere C carries a charge of +5.0 µC.Spheres A and B are touchedtogether and then separated. Spheres B andC are then touched and separated. Does sphereC end up with an excess or a deficiency ofelectrons and how many electrons is it?
Explanation / Answer
given the charge of the A is = - 2.0 C the charge of B is = -6.0 C the charge of C is = + 5.0 C the equilibrium chage on A and B after they touched andseperated is = {( -2.0-6.0) / 2 }C = -4.0 C the equilibrium chage on B and C after theytouched and seperated is = { ( -4.0 +5.0 ) / 2 }C =0.5 C as the positive charge of the C is decreased it end up withexcess number of electrons decreased charge q = 4.5 C number of elctron s = q / e where e is the charge of the elctron plug in and calculateRelated Questions
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