The position of a particle moving the x axis depends on thetime according to the

Question

The position of a particle moving the x axis depends on thetime according to the equation x=ct^2-bt^3, where x is in metersand t is in seconds. The numerical for c and b are 3.7 and1.0 respectivley. What distance does the particle cover in the first 4seconds? What is the displacement from t=0 to t=4.0 seconds? The position of a particle moving the x axis depends on thetime according to the equation x=ct^2-bt^3, where x is in metersand t is in seconds. The numerical for c and b are 3.7 and1.0 respectivley. What distance does the particle cover in the first 4seconds? What is the displacement from t=0 to t=4.0 seconds?

Explanation / Answer

Given equation   x =ct2-bt3           c =3.7 ; b = 1.0 a) at t = 1     x 1= 3.7 - 1       = 2.7 m      t = 2        x2 =3.7(2)2 - 1(2)3           =6.8m      t = 3      x 3= 3.7(3)2 -1(3)3         = 6.3m      t = 4      x 4= 3.7(4)2 -1(4)3         = -4.8 m -ve sign indicates reverse direction b)   the displace ment from t=0 to t=4s              x1+x2+x3+x4 =11m

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