1) A single slit forms a diffractionpattern, with the first minimum at an angle
ID: 1758654 • Letter: 1
Question
1) A single slit forms a diffractionpattern, with the first minimum at an angle of 40° fromcentral
maximum. Monochromatic light of450-nmwavelength is used. The same slit, illuminated bya
different monochromatic light source,produces a diffraction pattern with the second minimum ata
60° angle from the centralmaximum. The wavelength of this light, in nm, is closestto:
1)
2) Asingle slit, 2300 nm wide, forms a diffraction pattern whenilluminated by monochromatic light
of460-nmwavelength. The largest angle from the central maximum at which theintensity is zero
isclosest to:
2)
A)90° B) 81° C) 87° D) 78° E)84°
Explanation / Answer
2) The largest angle from the central maximum at whichthe intensity is zero is = 900 first minimum angle = 400 = 450*10-9m sin = m /a a = width of slit = m/sin where m = 1 a = 450*10-9/sin40 =700.9*10-9m for m = 2 angle = 600 = sina/m = 303*10-9m so A is correct answer. = sina/m = 303*10-9m so A is correct answer.Related Questions
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