A fiber with n=1.8 is surrounded by water with n=1.333 What isthe minimum angle

Question

A fiber with n=1.8 is surrounded by water with n=1.333 What isthe minimum angle of incidence for total internal reflection oflight traveling in the fiber? At what angle of incidence from the water side would lightreflected form the fiber be 100% polarized A fiber with n=1.8 is surrounded by water with n=1.333 What isthe minimum angle of incidence for total internal reflection oflight traveling in the fiber? At what angle of incidence from the water side would lightreflected form the fiber be 100% polarized

Explanation / Answer

(a)   minimum angle of incidence = sin-1 (n1 / n2) = sin-1 (1.333 /1.8) = .         = 47.8 degrees . (b)   tan = n2/n1 .                 angle = tan-1 (1.333 / 1.8) =    36.5degrees

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