The height of an object is 2.50cm. The object is on the opticalaxis 25cm to the

Question

The height of an object is 2.50cm. The object is on the opticalaxis 25cm to the left of a converging lens. A diverging lens isplaced 5.0cm to the right of the converging lens. The distance fromthe center of the converging lens to either of its focal points is15cm. the distance from the center of the diverging lens to eitherof its focal points is 5.0cm.

A)    A) Where on the optical axis is the final image?(‘’final image’’ means the image of theoptical after the light has passed through both lenses.)

B)    B) Is the final image real or virtual?

C)    C)Is the final image inverted?

D)   D) What is thefinal height of the object?

Explanation / Answer

converging lens f = 15cm               diverging lens   f = -5.0 cm

.

position of first image:   i = of / (o - f) = 25* 15 / (25 - 15) =    37.5 cm

.

second object distnce =   5.0 - 37.5 =   -32.5 cm

.

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