1) The atomic mass of 92 235 U is235.04 amu. How many Uranium atoms are containe

Question

1) The atomic mass of 92235U is235.04 amu. How many Uranium atoms are contained in 0.73 kg of pure92235U?

2) In 1990, according to the almanac, there were 5.33billion people living on the earth. If the 0.73 kg of92235U were divided evenly among thepopulation, how many atoms would each person have?
1) The atomic mass of 92235U is235.04 amu. How many Uranium atoms are contained in 0.73 kg of pure92235U?

2) In 1990, according to the almanac, there were 5.33billion people living on the earth. If the 0.73 kg of92235U were divided evenly among thepopulation, how many atoms would each person have?

Explanation / Answer

1) Since the atomic mass of U-235 is 235.04amu, each atom of U-235weight 235.04amu. Looking at a table of constants, 1amu = 1.66*10-27kg Therefore, 1 atom = 235.04amu = 235.04*1.66*10-27kg=3.901664*10-25kg (this is the weight of 1 atom) Therefore 1 atom = 3.901664*10-25kg Thus, 0.73 kg = ? atoms Number of atoms = 0.73/3.901664*10-25 =1.871*1024atoms 2) Since 0.73kg contains 1.871*1024atoms and those areevenly distributed among 5.33 billion people, each person has: 1.871*1024 / (5.33*109) =3.51*1014 atoms of U-235 in each person. I hope that helps.

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.