A concave mirror has a radius of curvature of 8.2 cm. (a) Determine the object p
ID: 1758050 • Letter: A
Question
A concave mirror has a radius of curvature of 8.2 cm. (a) Determine the object position for which theresulting image is upright andsix times the size of the object.Your answer is within 10% of the correctvalue. This may be due to roundoff error, or you could have amistake in your calculation. Carry out all intermediate results toat least four-digit accuracy to minimize roundoff error.cm
The problem states that it is wrong, but I don't understandwhy. Here is what I did 1/p + 1/q = 2/R R= 8.2cm Bc resulting image is upright and six timesthe size of the object. * q= -6p Thus 1/p + 1/ (-6p) = 2/R 5/6p = 2/R 5/6p= 2/8.2cm p = 3.42 But it says I am off by 10%.What am I doing wrong?!?!
(a) Determine the object position for which theresulting image is upright andsix times the size of the object.
Your answer is within 10% of the correctvalue. This may be due to roundoff error, or you could have amistake in your calculation. Carry out all intermediate results toat least four-digit accuracy to minimize roundoff error.cm
The problem states that it is wrong, but I don't understandwhy. Here is what I did 1/p + 1/q = 2/R R= 8.2cm Bc resulting image is upright and six timesthe size of the object. * q= -6p Thus 1/p + 1/ (-6p) = 2/R 5/6p = 2/R 5/6p= 2/8.2cm p = 3.42 But it says I am off by 10%.What am I doing wrong?!?!
Explanation / Answer
Given : Raius of curvature (R) = 8.2 cm Focal length (f) = R / 2 = 8.2 / 2 = 4.1 cm Magnification (M) = - v / u = 6 ==> v = - 6 u We know that : 1 / f = 1 / u + 1/ v ==> 1 / 4.1 = 1 / u - 1 / 6 u ==> 0.2439 = 1 / u [ ( 1 - 1/6) ] ==> 0.2439 = ( 1 / u )* (0.8334) ==> 0.2439 = 0.8334 / u or u = 0.8334 / 0.2439 = 3.4169 cm Hope this helps u!Related Questions
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