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W = F r cos *The displacement is that of the point ofapplication of the force *A

ID: 1758030 • Letter: W

Question

W = F r cos    *The displacement is that of the point ofapplication of the force    *A force does no work on the object if theforce does not move through a displacement    *The work done by a force on a moving objectis zero when the force applied is perpendicular to the displacementof its point of application I don't understand what the first bullet is stating. Theother two statements are clear to me. W = F r cos    *The displacement is that of the point ofapplication of the force    *A force does no work on the object if theforce does not move through a displacement    *The work done by a force on a moving objectis zero when the force applied is perpendicular to the displacementof its point of application I don't understand what the first bullet is stating. Theother two statements are clear to me. W = F r cos    *The displacement is that of the point ofapplication of the force    *A force does no work on the object if theforce does not move through a displacement    *The work done by a force on a moving objectis zero when the force applied is perpendicular to the displacementof its point of application I don't understand what the first bullet is stating. Theother two statements are clear to me.

Explanation / Answer

Solution: Basically what bullet 01 is stating is that if there's an appliedforce to a given object, then the object will undergo adisplacement along the direction of the applied force for howeverlong the force is applied (i.e. assuming the object has someinitial velocity, after the force is applied, its velocity isdifferent from which it started with, hence, the object acceleratedand work was done on it (i.e. energy was transferred to the objectwhich results in a change in kinetic energy)). For example, if youare on a horizontal surface and a force is applied parallel to thesurface on some object that was initially at rest, then the objectis expected to undergo displacement along the surface because it isconcurrent with the direction of the force being applied, etc. Note: if the above explanation doesn't clarify anything, pleaseinform me and I'll try to see what other methods of explanationwill make the problem easier to understand.