Suppose that a hydrogen atom in the ground state absorbs aphoton of wavelength 1

Question

Suppose that a hydrogen atom in the ground state absorbs aphoton of wavelength 10.4 nm. If the atom is ionized, what will be the kinetic energy of theelectron when it gets far away from its atom of origin? The valueof h is 1.05457e-34 J*s; the speed of light is2.99799e8 m/s; the value of h is 6.62607e-34 J*s; theRydberg constant for hydrogen is 1.09735e7m-1; the Bohrradius is 5.29177e-11 m; and the ground state energy for hydrogen13.6057 eV. 1eV=1.60218e-19 J. Answer in units of eV. Suppose that a hydrogen atom in the ground state absorbs aphoton of wavelength 10.4 nm. If the atom is ionized, what will be the kinetic energy of theelectron when it gets far away from its atom of origin? The valueof h is 1.05457e-34 J*s; the speed of light is2.99799e8 m/s; the value of h is 6.62607e-34 J*s; theRydberg constant for hydrogen is 1.09735e7m-1; the Bohrradius is 5.29177e-11 m; and the ground state energy for hydrogen13.6057 eV. 1eV=1.60218e-19 J. Answer in units of eV.

Explanation / Answer

the kinetic energy of the electron is K = (1/2)m * v2 -----------(1) According to De Broglie's theory we have = (h/m * v) or v = (h/m * ) ----------(2) from (1) and (2) or K = (1/2)m * (h/m * )2 = (1/2) *(h2/m * 2) h = 6.63 * 10-34 J-s,m = 9.1 * 10-31 kgand = 10.4 nm = 10.4 * 10-9 m According to De Broglie's theory we have = (h/m * v) or v = (h/m * ) ----------(2) from (1) and (2) or K = (1/2)m * (h/m * )2 = (1/2) *(h2/m * 2) h = 6.63 * 10-34 J-s,m = 9.1 * 10-31 kgand = 10.4 nm = 10.4 * 10-9 m

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