Unpolarized light with an average intensity of 750.0W/m 2 enters a polarizer wit

Question

Unpolarized light with an average intensity of 750.0W/m2 enters a polarizer with a vertical transmissionaxis. The transmitted light then enters a second polarizer. Thelight that exits the second polarizer is found to have an averageintensity of 125 W/m2. What is the orientation angle ofthe second polarizer relative to the first one?

a. 29.0°
b. 19.5°
c. zero degrees
d. 54.7°
e. 70.5° Unpolarized light with an average intensity of 750.0W/m2 enters a polarizer with a vertical transmissionaxis. The transmitted light then enters a second polarizer. Thelight that exits the second polarizer is found to have an averageintensity of 125 W/m2. What is the orientation angle ofthe second polarizer relative to the first one? 29.0° 19.5° zero degrees 54.7° 70.5°

Explanation / Answer

Unpolarized light with an average intensity I = 750.0 W/m2
Intensity of light after 1 st polariser I ' = I / 2                                                          = 375 W / m ^ 2 Intensity of the light after 2 nd polariser I " = I 'cos 2 given I " = 125 W / m ^ 2 cos = [ 125 / 375 ] from this the orientation angle of the second polarizerrelative to the first one is = cos -1 ([125/ 375 ] )                                                                                                                          = 54.73 degrees

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