2. If you place an object very far from themirror, what is the location of the i

Question

2. If you place an object very far from themirror, what is the location of the image?Answer: : 37.3cm
3. What is the magnification of theimage?Answer: :0

5. What is the magnification of theimage?Answer: :-1.7

_______________________________________________________________________________________

NEED ONLY HELP WITH QUESTIONS 6and 7 thanks

6. If a diverging lens of focal length -67.0cm is then placed 27.0 cm from the first lens on the opposite sideof the lens from the object, what is the location of the newimage?

Answer:   ?????

Hint: If you know themagnification of the first lens and the magnification of the secondlens, you are just about there.
7. What is the magnification due to thetwo-lens system?

Answer: ????

NEED ONLY HELP WITH QUESTIONS # 6and #7 thanks

Explanation / Answer

Focal length of the converging lens = 30cm Object distance to the converging lens = 47.65cm Then the image distance of the object to the converging lens =81.0cm Magnification of the converging lens = 1.7 Now if we placed a concave lens to the right of the converginglens, then the image formed due to the converging lens acts as anobject for the diverging lens. It is given that the diverging lens is placed 27.0 cm from thefirst lens on the opposite side of the lens, then the objectdistance to the diverging lens = 81.0cm - 27.0cm                                            = 54.0cm Focal length of the diverging lens = -67cm Then (1 / f) = (1 / do) + (1 / di)          -1 /67cm = (1 / 54.0cm) + (1 / di)             di = -29.9cm Now the magnification is m = (1.7)(-29.9cm / 54.0cm)                                          = -0.94
Hope this may helps you

Related Questions

Navigate

• Browse (All)
• Browse 2
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.